SYSTEM PARAMETERS
V
A
Entered as a magnitude (0–1). A balanced load with a lagging (inductive) power factor is assumed; Q is reported as inductive VAR.
QUICK PRESETS
CALCULATION SHEET
Real Power (P)
16.78 kW
Reactive Power (Q)
10.40 kVAR
Apparent Power (S)
19.75 kVA
Power Factor
0.850
System Details
Line-to-Line Voltage:380 V
Line-to-Neutral:219.4 V
Line Current:30 A
Phase Current:30 A
Derivation
- 01Configuration: WYE
- 02Assumption: balanced three-phase load (equal line currents, symmetrical line-to-line voltages) — S = √3 × VLL × IL holds only under this condition
- 03Assumption: power factor is entered as a magnitude and treated as lagging (inductive); Q is reported as inductive VAR
- 04Line-to-Line Voltage (VLL): 380 V
- 05Line-to-Neutral Voltage (VLN): 380 / √3 = 219.39 V
- 06Line Current (IL): 30 A
- 07Phase Current (Iph): 30 A (same as line current in Wye)
- 08Apparent Power (S): S = √3 × VLL × IL
- 09S = 1.732 × 380 × 30 = 19745.38 VA
- 10Real Power (P): P = S × cosφ
- 11P = 19745.38 × 0.85 = 16783.57 W
- 12Reactive Power (Q): Q = S × sinφ
- 13Q = 19745.38 × 0.527 = 10401.52 VAR
- 14Power Triangle: S² = P² + Q²
- 15Verification: √(16783.57² + 10401.52²) = 19745.38 VA ✓
REFERENCE — THREE-PHASE POWER FORMULAS
S = √3 × VLL × IL
P = S × cosφ
Q = S × sinφ
Configuration:
Wye: VLN = VLL / √3, IL = IPh
Delta: VLL = VPh, IL = √3 × IPh